Currently viewing  
 
bobhughes's profile:

Last Online: hidden
Member Since:2007-02-02

 bobhughes's most recent sites:
Title Views Votes Rating
?  . Cool Bomb 896
(3.67)
?  Baron Lasers takes a pill18818
(3.67)
?  Happy Birthday Uncle Jeff1246
(3.17)
?  WoW: mudkipzs vs longcat clanwar16611
(2.55)
?  my friend antwan & me at da pool724
(2.75)

 bobhughes's highest rated sites:
Title Views Votes Rating
?  SlimeTMND: Alicia Silverstone24,364813
(4.26)
?  Polyester: Footstomper Dance10,257527
(4.19)
?  Biggest 9/11 Mystery Solved12,313421
(4.17)
?  Don't.12,204380
(4.17)
?  Russians VS DongCopters10,647328
(4.13)

 bobhughes's most recent comments:
Site When Comment
2008-07-07 23:13:04
 
i didnt see the deeper meaning
+1
2008-07-07 23:09:52
 
lmao i dont remember this at all
+0
2008-07-07 13:02:57
 
It's better than most.
+0
2008-07-07 13:01:17
 
A topological space is said to be orthocompact if every open cover has an interior preserving open refinement. That is, given an open cover of the topological space, there is a refinement which is also an open cover, with the further property that at any point, the intersection of all open sets in the refinement containing that point is also open. If the number of open sets containing the point is finite, then their intersection is clearly open. That is, every point finite open cover is interior preserving.
+0
2008-07-07 12:06:34
 
A key property of elliptic operators is that they are almost invertible; this is closely related to the fact that their symbols are almost invertible. More precisely, an elliptic operator D on a compact manifold has a (non-unique) pseudoinverse D' such that DD' - 1 and D'D - 1 are both compact operators. An important consequence is that the kernel of D is finite-dimensional, because all eigenspaces of compact operators, other than the kernel, are finite-dimensional.
-5